20y^2-20y-5=20y

Solution for 20y^2-20y-5=20y equation:

20y^2-20y-5=20y

We move all terms to the left:

20y^2-20y-5-(20y)=0

We add all the numbers together, and all the variables

20y^2-40y-5=0

a = 20; b = -40; c = -5;
Δ = b2-4ac
Δ = -402-4·20·(-5)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-20\sqrt{5}}{2*20}=\frac{40-20\sqrt{5}}{40}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+20\sqrt{5}}{2*20}=\frac{40+20\sqrt{5}}{40}
$